oracle把日期转换成字符串 Oracle字符串转换为日期格式?
Oracle字符串转换为日期格式?
WITH t AS (SELECT "abcdefghijklmn" AS a FROM dual UNION ALL SELECT "abcdefgh" AS a FROM dual UNION ALL SELECT "abcd" AS a FROM dual) SELECT CASE WHEN length(lpad(t.a, 8, "0")) = 8 THEN lpad(t.a, 8, "0") ELSE substr(t.a, 1, 8) END AS a FROM t
oracle数据库怎么转换时间格式?
可以用to_date("日期类型字符串","要转化的日期类型")函数进行日期格式转换sql:selectto_date("1990-12-1212:12:32","yyyy-MM-ddhh24:mi:ss")fromdual解释:此语句的输出结果就是“1990-12-1212:12:32”(日期类型)。后面的日期类型格式可以根据实际需要修改如改为:selectto_date("1990-12-1212:12:32","yyyy-MM-dd)fromdual输出结果就是“1990-12-12”.
oracle把日期转换成字符串 oracle中日期格式转换 tochar转换日期格式
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