oracle截取特定字符后面的字符串 oracle怎么截取指定字符后面的字符串，或者删除指定字符前面的字符串也行？

oracle怎么截取指定字符后面的字符串，或者删除指定字符前面的字符串也行？

取最后一个后面的字符select substr("D:AssetsManagementresourceehcachetest.txt"，1 (select instr ("D:AssetsManagementresourceehcachetest.txt"，""，1，(select length("D:AssetsManagementresourceehcachetest.txt") - length(replace("D:AssetsManagementresourceehcachetest.txt"，""，"")) from dual)) from dual)，length("D:AssetsManagementresourceehcachetest.txt")-(select instr ("D:AssetsManagementresourceehcachetest.txt"，""，1，(select length("D:AssetsManagementresourceehcachetest.txt") - length(replace("D:AssetsManagementresourceehcachetest.txt"，""，"")) from dual)) from dual)) from dual如果前面D:AssetsManagementresourceehcache是固定的就直接replace了select replace("D:AssetsManagementresourceehcachetest.txt"，"D:AssetsManagementresourceehcache"，"") from dual

oracle如何截取指定字符串？

oracle中，截取某个字符串前的字符需要用instr函数和substr函数共同完成。工具：oracle 10g步骤：1、以截取字符串“210-1106000001”中“-”前的部分为例。2、执行语句为：select substr("210-1106000001"，1，instr("210-1106000001"，"-")-1) from dual3、结果为：instr函数语法：instr( string1， string2， start_position，nth_appearance )参数含义：substr函数语法：substr(strings|express，m，[n])参数含义：strings|express ：被截取的字符串或字符串表达式。m 从第m个字符开始截取。n 截取后字符串长度为n。

oracle截取特定字符后面的字符串 oracle根据空格截取字符串 oracle截取字符串前几位

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